出现这个问题是你分别在两个地方载入一模一样的包，但是两个包的路径不是同一个地方的，例如你写的client，有个地方载入了client.pb.go ，有个地方载入了server.pb.go，client.pb.go和server.pb.go一模一样，就会出现这种报错，解决方案就是同样的包只载入一个即可
leetcode add-two-numbers
2. Add Two Numbers
我的github有源码https://github.com/ttllpp/leetcode
题目
You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
You may assume the two numbers do not contain any leading zero, except the number 0 itself.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8解题思路
(2 -> 4 -> 3)是 342
(5 -> 6 -> 4)是 465
(7 -> 0 -> 8)是 807
342 + 465 = 807所以，题目的本意是，把整数换了一种表达方式后，实现其加法。
设计程序时候，需要处理的点有
- 位上的加法，需要处理进位问题，进位有个规律，a/10取整，可以得到当前进位的值，a%10可以得到当前位的值
- 如何进入下一位运算
- 按位相加结束后，也还需要处理进位问题。
leetcode two-sum
1. Two Sum
我的github有源码https://github.com/ttllpp/leetcode
题目
Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:
Given nums = [2, 7, 11, 15], target = 9,
Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].解题思路1
a + b = target也可以看成是
a = target - b然后依次寻找差值a
解题思路2
a + b = target最暴力的方法，直接两个循环
解题思路3
a + b = target也可以看成是
a = target - b在map[整数]整数的序号中，可以查询到a的序号。这样就不用嵌套两个for循环了。
golang高性能string转byte
golang高性能string转byte
func StringBytes(s string) []byte {
return *(*[]byte)(unsafe.Pointer(&s))
}
func BytesString(b []byte) string {
return *(*string)(unsafe.Pointer(&b))
}
func OriginStringBytes(s string) []byte {
return []byte(s)
}
func OriginBytesString(b []byte) string {
return string(b)
}然后分别测试
package main
import (
"math/rand"
"testing"
)
var letters = []byte("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")
var a = randSeqString(10000)
var c = randSeqByte(10000)
func randSeqString(n int) string {
b := make([]byte, n)
for i := range b {
b[i] = letters[rand.Intn(len(letters))]
}
return string(b)
}
func randSeqByte(n int) []byte {
b := make([]byte, n)
for i := range b {
b[i] = letters[rand.Intn(len(letters))]
}
return b
}
func Benchmark_StringBytes(b *testing.B) {
for i := 0; i < b.N; i++ { //use b.N for looping
StringBytes(a)
}
}
func Benchmark_BytesString(b *testing.B) {
for i := 0; i < b.N; i++ { //use b.N for looping
BytesString(c)
}
}
func Benchmark_OriginStringBytes(b *testing.B) {
for i := 0; i < b.N; i++ { //use b.N for looping
OriginStringBytes(a)
}
}
go test -test.bench=".*"
goos: linux
goarch: amd64
pkg: test/test5
Benchmark_StringBytes-4 2000000000 0.72 ns/op
Benchmark_BytesString-4 2000000000 1.16 ns/op
Benchmark_OriginStringBytes-4 300000 4649 ns/op
PASS
ok test/test5 5.398s
docker版本的nginx+php+mysql+memcache+redis
花点时间整理了一个docker版本的lnmp+memcache+redis
docker nginx+mysql+php+memcached+redis
github地址：https://github.com/ttllpp/dnmp
1.目录结构
/
├── mysqlCnf mysql
│ └── my.cnf mysql配置文件
├── redis redis
│ └── redis.conf redis配置文件 开启全内存保存，最大64m
├── php-fpm php-fpm
│ ├── php.ini php.ini
│ └── Dockerfile build文件
├── nginx nginx
│ ├── cert 证书目录
│ ├── fastcgi.conf fastcgi配置
│ ├── logs 访问日志目录
│ ├── nginx.conf nginx配置
│ └── conf.d nginx配置
│ └── default.conf 网站配置
├── mysql mysql数据目录
├── php php代码目录
└── memcached memcached 最大64m2.启动方式
docker-compose up -d
3.php-fpm
php安装扩展为
- PHP版本7.2.12
- mysqli
- swoole1.10.4
- igbinary2.0.8
- memcached3.0.4
- redis4.2.0